Oct 302009
Consider TTI = 20ms
peak data rate = 64 kbps
trasnport block size = 336 bits
RLC SDU size = 500 bytes
SN=6, 8 are dropped.
SN = Sequence Number
P = Poll bit
The physical layer combines the transport blocks together, interleaves them and then transmits them via two radio frames.
Thus, RLC PDUs in the receiver cannot be recovered until all of the data from that 20 ms TTI has been received.
SN=12, Poll bit is set.
At receiving side, it took 20ms for processing. Then send STATUS PDUs.
After 20ms, the missing SN=6, 8 will be retransmitted.
